If friction loss scales linearly with length, what is the friction loss for 180 m of the same hose given 90 m has 490 kPa?

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Study for the NFPA 1002 Pump Operations Test with multiple choice questions and detailed explanations. Ace your exam with confidence!

Multiple Choice

If friction loss scales linearly with length, what is the friction loss for 180 m of the same hose given 90 m has 490 kPa?

Explanation:
Friction loss in a hose is proportional to the length when flow, diameter, and other conditions stay the same. Doubling the length doubles the friction loss. So if 90 m yields 490 kPa, 180 m yields 490 × 2 = 980 kPa. You can also see this by per-meter loss: 490 kPa / 90 m ≈ 5.44 kPa per meter, times 180 m gives about 980 kPa. The other numbers would require a different length or a non-linear relationship, which isn’t the case here.

Friction loss in a hose is proportional to the length when flow, diameter, and other conditions stay the same. Doubling the length doubles the friction loss. So if 90 m yields 490 kPa, 180 m yields 490 × 2 = 980 kPa. You can also see this by per-meter loss: 490 kPa / 90 m ≈ 5.44 kPa per meter, times 180 m gives about 980 kPa. The other numbers would require a different length or a non-linear relationship, which isn’t the case here.

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